3x^(2/3)-17x^(1/3)-6=0

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Solution for 3x^(2/3)-17x^(1/3)-6=0 equation: 


x in (-oo:+oo)

3*x^(2/3)-(17*x^(1/3))-6 = 0

3*x^(2/3)-17*x^(1/3)-6 = 0

t_1 = x^(1/3)

3*t_1^2-17*t_1^1-6 = 0

3*t_1^2-17*t_1-6 = 0

DELTA = (-17)^2-(-6*3*4)

DELTA = 361

DELTA > 0

t_1 = (361^(1/2)+17)/(2*3) or t_1 = (17-361^(1/2))/(2*3)

t_1 = 6 or t_1 = -1/3

t_1 = -1/3

x^(1/3)+1/3 = 0

1*x^(1/3) = -1/3 // : 1

x^(1/3) = -1/3

( -1/3 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 6

x^(1/3)-6 = 0

1*x^(1/3) = 6 // : 1

x^(1/3) = 6

x^(1/3) = 6 // ^ 3

x = 216

x = 216

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